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Lie derivation

Lie derivation appears in a wide contexts. It is based on the following observation. Let $ A$ be a commutative ring. Let $ B$ be a commutative $ A$ -algebra. Let $ \epsilon$ be the dual number.

$\displaystyle A_\epsilon=A[\epsilon]/(\epsilon^2), \quad
B_\epsilon=B[\epsilon]/(\epsilon^2) .
$

Then for any $ x\in \operatorname{Hom}_B(\Omega^1_{B/A},B)=\operatorname{Der}_A(B,B)$ , we define

$\displaystyle \operatorname{id}+\epsilon x: B_\epsilon \to B_\epsilon.
$

It is an $ A_\epsilon$ -algebra automorphism of $ B_\epsilon$ which reduces to the identity when we put $ \epsilon=0$ . So any natural construction on algebras may be transformed by this map. Among such constructions is the modules of differential forms, modules of derivations, tensor products of them, and the dual of them.

We may also introduce

$\displaystyle L_x: \Omega^\bullet_{B/A} \to \Omega^\bullet_{B/A}
$

to be the unique $ A$ -linear map which satisfies the following properties.
  1. $ L_x(f)=x.f=\langle x, d f\rangle $ for any $ f \in B$ .
  2. $ L_x(d f)=d (\langle x, d f\rangle)$ for any $ f \in B$ .
  3. $ L_x$ is an even derivation. That means,

    $\displaystyle L_x(\alpha \wedge \beta)
=(L_x\alpha)\wedge \beta +\alpha \wedge ...
...ll \alpha \in \Omega^\bullet_{B/A},\
\forall \beta \in \Omega^\bullet_{B/A}).
$

Other useful Lie derivation is that for vector fields. Namely, Let $ x,y$ be two $ A$ -derivations from $ B$ to $ B$ . Then we define

$\displaystyle L_x(y)=[x,y](=xy-yx).
$

Lie derivations commute with contractions. Namely,

$\displaystyle L_x \langle y, df\rangle
=\langle L_x (y), df\rangle
+\langle y, L_x(df)\rangle \quad (\forall x, y \in \operatorname{Der}_A(B), \forall f\in B).
$

We leave it the reader to do the detailed discussion.


next up previous
Next: Relations of derivations. Up: some linear algebra Previous: interior derivation
2007-12-26